a+3/a+7-2a-4/a^2+3a-28=2-a/4-a

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Solution for a+3/a+7-2a-4/a^2+3a-28=2-a/4-a equation: 



a+3/a+7-2a-4/a^2+3a-28=2-a/4-a

We move all terms to the left:

a+3/a+7-2a-4/a^2+3a-28-(2-a/4-a)=0



Domain of the equation: a!=0

a∈R





Domain of the equation: a^2!=0

a^2!=0/

a^2!=√0

a!=0

a∈R





Domain of the equation: 4-a)!=0

We move all terms containing a to the left, all other terms to the right

-a)!=-4

a!=-4/1

a!=-4

a∈R



We add all the numbers together, and all the variables

a+3/a-2a-4/a^2+3a-(-1a-a/4+2)+7-28=0

We add all the numbers together, and all the variables

2a+3/a-4/a^2-(-1a-a/4+2)-21=0

We get rid of parentheses

2a+3/a-4/a^2+1a+a/4-2-21=0

We calculate fractions

We do not support eapression: a^3

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